Question

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Answer 1

Hey there !

Solution :

Given :

y = x³ - 3x² + 6 

So let us differentiate this function so that we can get the critical values for y.

y = $\frac{d}{dx} ( x^3 ) - 3 * \frac{d}{dx} ( x^2 ) + \frac{d}{dx} ( 6 )$

y = $3x^2 - 3 * 2x + 0$

y = 3x² - 6x 

Therefore finding the values for x we get,

3x ( x - 2 ) = 0

=> 3x = 0 ; x - 2 = 0

=> x = 0 ; x = 2

Hence x = ( 2,0 )

Maximum value = 2, Minimum value = 0

Hope my answer helped :-)