Question

Hg2 2+ reduces Fe 3+ in presence of [SCN] 1- through Hg2+/Hg2 2+ couple is more oxidising than Fe3+/ Fe2+ couple. 2Hg 2+/Hg2 2+ =+0.92 Fe3+/Fe2+ =+0.77

Answer 1

hey,

For the reaction:

2Ag+

+ 2Hg → 2Ag + Hg2

2+

E˚Ag+/Ag = 0.80 V E˚Hg2

2+/Hg = 0.79 V

Predict the direction in which the reaction will proceed if:

[Ag+

] = 10-1mol/h [Hg2+] = 10-3mol/h

Ans:

Cell reaction is:

2Ag+

+ 2Hg → 2Ag + Hg2

2+

E cell = E˚ cell – 0.0591/2 log [Hg2

2+]/ [Ag+

]

2

= (0.80V-0.79V) -0.0591/2 log 10-3

/ (10-1

)

2

= 0.01V- 0.0591/2 (-1) = 0.01+0.0295

= 0.0395V

Since E cell is positive,

the reaction will be spontaneous in the forward direction.

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