Question

Hgcl2 + sncl2 in hg2cl2 + sncl4 of oxidation method.
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Answer 1

2 HgCl2 + SnCl2 → SnCl4 + Hg2Cl2

This is an oxidation-reduction (redox) reaction:

SnII - 2 e- → SnIV

(oxidation)

2 HgII + 2 e- → 2 HgI

(reduction)

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