Question

HI acid whan heated with conc. H2SO4 forms ​

Answer 1

Explanation:

HI reduces sulphuric acid sulphur dioxide and itself is oxidised to iodine. Hence, HI is prepared by heating KI with conc. Phosphoric acid.

Answer 2

$HI$ reduces sulphuric acid sulphur dioxide and itself is oxidized to iodine.

Explanation:

• $HI$ reduces sulphuric acid to sulphur dioxide and itself is oxidized to iodine.
• $KI+H2SO4 ------ KHSO4 + KI$
• $H2SO4 + 2HI ----- SO2 + I2 + H2O$
• Hence, $HI$ is prepared by heating $KI$ with conc. phosphoric acid.
• As $HBr$ also reacts in the same way as $HI$ undergoes
• $HI$ cannot be prepared by the action of conc.$H2SO4$ on $KI$because $H2SO4$ is an oxidizing agent and $HI$is a strong reducing agent.
• $HI$ reduces sulphuric acid to sulphur dioxide and itself is oxidised to iodine.