Question

Hi ,Answer my question brainly...

A light ray is incident on air liquid interface at 45degree and is refracted at 30degrees what is the refractive index of liquid for what angle of incidence will be the angle between reflected ray and refracted ray!

Answer 1

Answer:

your answer is here !

Explanation:

Given:

Angle of incidence i = 45°

Angle of refraction r = 30°

 

refractive index =n=sin i /sin r 

=sin45°/sin 30°

=1/√2/1/2⇒2/√2⇒√2=1.4.14

Given the angle between the reflected and

refracted ray = 90°

 It means angle of reflection (r) + angle of incidence (i) = 90°

 Angle of refraction (r) = (90° - i) 

But refractive index n =  sin i/ sin r

=sin i/ sin(90-i)

=sin i/ cos i (∵sin(90-θ)=cos θ)  

From Natural tangent tables tan 54.7° = 1.414 = tan i

The angle of incidence i = 54.7°

follow me !

Answer 2

$\huge\mathfrak{ANSWER}$ :-

Explanation:

Let’s know ,

What is Refraction ?

•The process of changing speed when light travels from one medium to another is called refraction of light.

What is refracted Ray ?

•The Ray which refracted from a surface is called refracted Ray.

What is Refractive index?(absolute)

•The ratio of speed of light in vacuum and the speed of light in medium.

For Answer,Refer attachment!