Question

hi answer the question

Answer 1

angle A=35°(V. O. A)

angle ACB=180°-100(LINEAR PAIR)
=80°

BY ANGLE SUM PROPERTY OF TRIANGLE angle A+B+C=180°
35°+80°+angle ABC=180°
angle abc=180°-115°
=65°

Answer 2

hey..
angle ACD =100°
angle ACB + angle ACD = 180°
angle ACB + 100 = 180
angle ACB = 80°✓

angle OAP = angle BAC = 35°✓
in∆ABC

angle ACB+ angle BAC+ angle ABC = 180 ° ( A.S.P)
80° + 35° + angle ABC = 180°
angle ABC = 180-115
angle ABC = 65°✓


hope it's help you