Question

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Answer 1

Explanation:

Hello! mates here's Ur ans..

Given;

Temperature of A = 10° C.

Temperature of B= 25° C .

Temperature of C= 40° C.

and, also given;

A mixed with B= 15 so, 25-10=15..( when they mixed).

and, B mixed with C = 40- 25= 15+ 15= 30° .

when, A mixed with C= C+ A - 30

= 40+10-30

= 50 - 30= 20°.

hence , the ans..is (b) 20°..

here, is Ur ans..mates. hope it's helpful..

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Answer 2

Answer:

$\large\boxed{{\bf T = 16^{\circ}\:C}}$

Solution :

m × C × ∆T = m' × C' × ∆T' (by law of calorimetry, heat lost by one substance must be equal to that gain by the other when mixing )

$\sf C_A (15 - 10) = C_B (25 - 15)$

$\sf C_A = 2C_B$

Also, $\sf C_B (30 - 25) = C_C (40 - 30)$

$\sf C_B = 2C_C$

Let temprature be T when A and C are mixed then,

➨$\sf C_A (T - 10) = C_C (40 - T)$

➨$\sf 4C_C (T - 10) = C_C (40 - T)$

➨$\sf 4 T - 40 = 40 - T$

➨$\sf 5 T = 80$

➨$\sf T = \dfrac{80}{5}$

➨$\underline{\boxed{\gray{\bf T = 16^{\circ}C}}}$$\bigstar$

Therefore, if A and C are mixed the temperature of the mixture is T = 16° C.