Physics, asked by basavarajk1245, 3 months ago

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Answered by Anonymous
28

\underline\mathfrak{Answer}

The current,energy consumed in 50 hours and total cost are 6 A, 75 kW-h and 165 Rs.

Explanation:

Given that,

Power P = 1500 W

Voltage V = 250 V

Time t = 50 hours

\\

(I). We need to calculate the current

The power is defined as,

P =VIP=VI

Where, P = Power

V = voltage

I = current

The current is equal to the power divided by the voltage

I = \dfrac{P}{V}I=VP \\ Put  \: the \:  value \:  in \: the \:  formula \\ I = \dfrac{1500}{250} \\ I=2501500 \\ I =6 \\  AI=6 A \\

\\

(II). We need to calculate the energy consumed in 50 hours

The energy is defined as,

E = P\times TE \\ =P×T \\E = V\times I\times TE \\=V×I×T \\ Where, T = time\\ Put \:the\:value\:into\:formula\\ E = 250\times6\times50E \\=250×6×50\\E=75000\:W-hE \\ =75000 W−h\\E =75\:kW-hE\\ =75 kW−h \\

\\

(III). The cost of energy consumed of 2.20 per unit.

We need to calculate the total cost

The \:  total \:  cost \:= 2.20\times752.20×75 \\ Total \:  cost  \: =165 Rs.

Hence, The current,energy consumed in 50 hours and total cost are 6 A, 75 kW-h and 165 Rs.

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