Question

HI ANYONE PLSS ANSWER THIS PLSSS
1) A train accelerates from 36 km/h to 54 km/h in 10 sec.Then find DISTANCE
-9TH GRADE
ARSHAD PLSS

Answer 1

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See the attachment dear

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Answer 2

Inital velocity(u)=36 km/hr=10m/s

Final velocity=54km/hr=15m/s

Time=10 second

Disance(s)=?

First we have to find the acceleratiom

V=u+at

15=10+10(t)

15=10+10t

5=10t

a=1/2

NOW USING THE SECOND QUATION

S=ut+1/2(a)(t)^2

S=10×10+1/2×1/2×100

S=100+25

s=125m

THUS,The distance travelled by the train is 125m.