Question

hi army please help to find the answer​

Answer 1

$\mid \underline{ \boxed{ \sf \: b. \quad \frac{1}{6} \quad}}\mid$

No. of D's in the word = 1

Total no. of letters = 6

Hence, probability of getting the letter D,

$\sf p(D) = \frac{no. \: of \: D's}{ \quad no. \: of \: total \: letters \quad} = \frac{1}{6}$

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Answer 2

Hi....................