Question

Hi
@shubh78032 u always answer my question thankyou .

A coin is tossed 1000 times with the following .frequensis .
head:455 tail:545​

Answer 1

$[]\huge\mathfrak\green{Answer}$

since the coin tossed is 100times the total number of trials is 1000 let us call the event of getting a head of a getting a tail as E and F respectively then the number of time I.e the number of times a head come up. is 455

$\large\mathfrak\pink{The \: probaility \: of \: e \: \frac{number \: of \: heads}{total \: no \: of \: trial} }$

$\large\mathfrak\pink{P(E) = \frac{455}{1000 = }0.455 }</p><p>$

Similarly, the the probability of the event of getting a tail .

$\large\mathfrak\pink{ \frac{number \: of \: tails}{total \: number \: of \: trial} }</p><p>$

[tex]\large\mathfrak\pink{P(F) = \frac{545}{1000} = 0.545 }[

P(E)+P(F)= 0.455+0.545= 1

and E and F are the only two possible out come of each trial