Hi
@shubh78032 u always answer my question thankyou .
A coin is tossed 1000 times with the following .frequensis .
head:455 tail:545
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since the coin tossed is 100times the total number of trials is 1000 let us call the event of getting a head of a getting a tail as E and F respectively then the number of time I.e the number of times a head come up. is 455
Similarly, the the probability of the event of getting a tail .
[tex]\large\mathfrak\pink{P(F) = \frac{545}{1000} = 0.545 }[
P(E)+P(F)= 0.455+0.545= 1
and E and F are the only two possible out come of each trial
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