English, asked by s1266aakansha782696, 3 months ago

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What is the work to be done to increase the velocity of a car from 20km/h to 40km/h if the mass of the car is 2000 kg?

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Answered by nayakdebi
2

Answer:

Here ur answer.

Given, intial velocity ,u- 20km/hr = 20×5/18=50/9 m/s

final velocity, v- 40 km/hr=40×5/18=100/9 m/s

mass, m= 2000kg

2 2

Workdone = 1×mv /2-1×mu /2

==>W=m(v2- u2) /2

=2000[100/9×100/9-50/9×50/9]/2

= 2000(10000/81 -2500/81) /2

=2000(7500/81) /2

=92,592.5J


nayakdebi: hope it will be helpful
s1266aakansha782696: Thank you
Answered by TheUnknownLily
31

\boxed{\underbrace{\overbrace{\bf{\orange{QUESTION}}}}}

What is the work to be done to increase the velocity of a car from 20km/h to 40km/h if the mass of the car is 2000 kg?

\boxed{\underbrace{\overbrace{\bf{\green{ANSWER}}}}}

: \longrightarrow \bf{Initial\: velocity\:(u)} \:=\: 20km/h

\implies u \:=\: 20 \times \bf{\frac{1000}{60\:×\:60}}

\implies u \:=\: \bf{\frac{50}{9}}

: \longrightarrow \bf{Final\: velocity\:(v)} \:=\: 40km/h

\implies v \:=\: 40 \times \bf{\frac{1000}{60\:×\:60}}

\implies v \:=\: \bf{\frac{100}{9}}

 \therefore Work Done , W = \frac{1}{2} \times mv²

\implies W \:=\: \frac{1}{2} \times 2000 \:×\: ( v² - u² )

 \implies W \:=\: \frac{2000}{2} \times ( (\frac{100}{9})^{2} \:-\: (\frac{50}{9})^{2} )

\implies W \:=\: 1000 \times \frac{10000}{81} \:-\: \frac{2500}{81}

\implies W \:=\: 1000 \times \frac{7500}{81}

\implies W \:=\: 92592.9 ( approx )


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