hi can anyone answer this question
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The question is
"Let x = 0.123456789101112.....998999 where the digits are obtained by writing the integers through 999 in order. Then the 2014th digit to right of decimal point is ?"
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9
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The digits are written first as 1 to 9
Total number of digits in 1 to 9 = 9
Then,
10 to 99
Total number of digits in 10 to 99 = 2 ( 99 − 10 + 1) = 180
So,
From 1 to 99 number of digits = 9 + 180 = 189
We need to find 2014th digit,
2014 − 189 = 1825
So, we need to find 1825th digit in 100 to 999
1825/3=808×1/3
So, required number will be first digit of 809th number starting from 100.
809th number starting from 100 = 100 + 809 − 1 = 908
As first digit of 908 is 9.
Hence, required answer is 908.
✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️
The digits are written first as 1 to 9
Total number of digits in 1 to 9 = 9
Then,
10 to 99
Total number of digits in 10 to 99 = 2 ( 99 − 10 + 1) = 180
So,
From 1 to 99 number of digits = 9 + 180 = 189
We need to find 2014th digit,
2014 − 189 = 1825
So, we need to find 1825th digit in 100 to 999
1825/3=808×1/3
So, required number will be first digit of 809th number starting from 100.
809th number starting from 100 = 100 + 809 − 1 = 908
As first digit of 908 is 9.
Hence, required answer is 908.
✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️
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3
the answer is 7 according to the answer key of my book....i am too in an urgent need of finding a solution to this question , please give the correct answer.
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