Hi,Can you plz explain me -
If tan 2A= cot (A-18°),where 2A is an acute angle, find the value of A
Arvind9747:
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tan 2A = cot ( A - 18 )
cot ( 90 - 2A) = cot ( A - 18 )
90 - 2A = A - 18
3A = 108
A = 36°
HOPE IT HELPS
KRITI 1123
cot ( 90 - 2A) = cot ( A - 18 )
90 - 2A = A - 18
3A = 108
A = 36°
HOPE IT HELPS
KRITI 1123
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