hi could u plzz help me in this one
find two consecutive natural numbers whose square have the sum 85
Answers
Answered by
4
Ans :
6,7 or -6, -7
Hint :
Let the natural numbers be x and x + 1. Then, by hypothesis, we have
x
2
+(x+1)
2
=85.
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Answered by
1
Answer:
6,7 or -6, -7
6,7) and (-7,-6) are two pairs of consecutive numbers whose square have the sum of 85.
Let one number be x and the other number be x+1. (Since they are consecutive)
Now we have, x^2 + (x+1)^2=85
x^2 +x^2+2x+1=85
2x^2 +2x+1=85
2x^2 +2x - 84=0
x^2 +x - 42=0
(x+7)(x-6)=0
Therefore, x=6 and x+1=7 or x=-7 and x+1=-6.
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