Question

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i need ans of this que i m not able to solve it i need correct ans

Answer 1

1. Let the distance covered by the peacock be AC = x m
Hence the distance covered by the snake is DC = x m
In right ΔABC, by Pythagoras theorem we have
AC2 = AB2 + BC2
x2 = 92 + (27 – x)2
⇒ x2 = 81 + 729 – 54x + x2
⇒ 54x = 810
∴ x = 15

2. Let the total no. of swans = x
No. of swans playing on the shore = 7/2 √x
Remaining swans = 2
A/Q x=7/2 √x+2
x-2 = 7/2 √x
2(x-2) = 7√x
4(x-2)² = 49x
4(x²-4x+4) = 49x
4x²-65+16 = 0
(x-16) (4x -1) = 0
x-16 = 0 or 4x-1 = 0
x = 16 or x = 1/4
Since, the no. of swans cannot be 1/4
∴ x = 16
The total no.of swans = 16