Hi everyone Plz answer this easy. maths question but Plz with reason no direct answering
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54 is the ans
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one angle be x and other angle be y
Two complementary angles are such that two times the measure of one is equal to three times the measure of the other
2x = 3y
x = 3y/2...........(1)
complementary angles are such that sum of angles is equal to 90°
so, x + y = 90°.........(2)
substitute (1) in (2)
3y/2 + y = 90°
5y/2 = 90°
5y = 90°*2
y = 180°/5
y = 36°
so, x = 3y/2 = 3*36°/2 = 108°/2 = 54°
larger angle is x = 54°
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Two complementary angles are such that two times the measure of one is equal to three times the measure of the other
2x = 3y
x = 3y/2...........(1)
complementary angles are such that sum of angles is equal to 90°
so, x + y = 90°.........(2)
substitute (1) in (2)
3y/2 + y = 90°
5y/2 = 90°
5y = 90°*2
y = 180°/5
y = 36°
so, x = 3y/2 = 3*36°/2 = 108°/2 = 54°
larger angle is x = 54°
#mark as brainliest
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