hi everyone,tomorrow is my exam so please help me in finding magnetic field intensity at the centre of ellipse please please please help me tomorrow is my exam ..
Answers
Answer:
The Attempt at a Solution In class we found the magnetic field at a point in space (point P) caused by the current running through a wire. Point P is equidistant from every point on the wire call this distance R. dS is a differential element that points along the wire and r hat points toward point P. The angle between dS and r hat is 90 degrees at all points. The point P is essentially the center of a circle and the wire outlines the edge of a circle. B= μ o i 4 π μoi4π∫ d → S × ^ r r 2 dS→×r^r2 B= μ o i 4 π μoi4π∫ | d → S | | ^ r | s i n θ r 2 |dS→||r^|sinθr2 B= μ o i 4 π R 2 μoi4πR2∫ d S ( 1 ) s i n 90 o dS(1)sin90o B= μ o i S 4 π R 2 μoiS4πR2 S=R θ 1 θ1 where θ 1 θ1 is the angle swept out between one end of the wire and point P and the other end the wire and point P. B= μ o i R θ 1 4 π R 2 μoiRθ14πR2 B= μ o i θ 1 4 π R μoiθ14πR OK punchline. I was thinking how could I find the magnetic field at point P due to a piece of wire that outlines a portion of an ellipse. This would mean that the angle between dS and r hat would be a different angle at every point on the wire and the distance between point P and the wire would be different at every point along the wire.
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Answer:
Explanation:
Take out difference between velocity and..... u know