Hi eveyone I need to find the hcf of 56 and 814 using euclid's divion algorithm PLs help..thank you
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here is your answer....
in the form of
a=bq+r
814=56*14+30
56=30*1+26
30=26*1+4
26=4*6+2
4=2*2+0
so the HcF of 56 and 814 is =2
that's all......
in the form of
a=bq+r
814=56*14+30
56=30*1+26
30=26*1+4
26=4*6+2
4=2*2+0
so the HcF of 56 and 814 is =2
that's all......
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