hi experts plzz answer this question
Evaluate:
1. 7(a²-b²)³ +7(b²-c²)³+7(c²- a²)³/(a-b)³+(b-c)³+(c-a)³
2.if √2x=√3y =√5,prove that 2√2x³+3√3³-5√5+3√30xy=0
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hey mate here is ur answers
i think there are some little bit mistake in 2nd question...it should be 3root3 y^3 be there nd root2x=root3y= -root5 beacuase if minus in root5 then only it will come -5root5
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Answer:
Step-by-step explanation:
we use the fact that if a+b+c = 0, then a³+b³+ c³ = 3 a b c.
(a² - b²) + (b² - c²) + (c² - a²) = 0...
also (a-b) + (b-c)+ (c-a) = 0
we assume that a ≠b ≠ c.
hence,
(a²-b²)³+(b²-c²)³+(c²-a²)³ ÷ (a-b)³+b-c)³+(c-a)³
= 7* 3 (a² - b²) (b² - c²) (c² - a²) /7* [ 3 (a - b) (b - c) ( c -a) ]
= ( a+b) (b + c) ( c +a)
∵ a² - b² = (a -b) (a+b) and similarly other terms.
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