Question

hi...explain please...​

Answer 1

Answer:

[Cu(NH₃)₄]²⁺

Explanation:

Magnetic moment = √n(n + 2)

n = no of unpaired electrons

Magnetic moment of [Cu(NH₃)₄]²⁺ = √n(n + 2) = √1(1 + 2) = √3 BM (Cu²⁺ ion = [Ar] 3d⁹ 4s⁰ )

(4s orbital is empty and d orbital has 9 electrons with 1 orbital 1 electron)

Whereas Ni²⁺ in [Ni(CN)₄]²⁻, Ti⁴⁺ in TiCl₄ and Co²⁺ in  [COCl₆]⁴⁻ has has 2,0 and 3 unpaired electrons respectively.

So answer is [Cu(NH₃)₄]²⁺

Cu²⁺ ion = [Ar] 3d⁹ 4s⁰

HOPE IT HELPS YOU

PLEASE MARK ME AS THE BRAINLIEST

Answer 2

Answer:

Answer is Option C

Electronic configuration of Cu :- 3d10 4s1

Oxidation State = +2

so 3d^9 4s0

NH3 is strong field Li.g.and so pairing takes place