Question

Hi frends!
plz answer my question............​

Answer 1

Step-by-step explanation:

ANSWER:-

p(x) = 3x²-1 is the polynomial

Given zeroes

$\frac{ - 1}{ \sqrt{3} }$

and

$\frac{2}{ \sqrt{3} }$

Simply placing the values in place of x,

If it be comes equal to zero, then it will he known as zeroes of polynomial.

$3 {( \frac{ -1 }{ \sqrt{3} } )}^{2} - 1$

$3 \times \frac{1}{ 3} - 1$

$1 - 1 = 0$

So , -1/ root 3 is a zero of polynomial.

Placing second one now,

$3 {({ \frac{2}{ \sqrt{3}}})}^{2} - 1$

$3 \times \frac{4}{3} - 1$

$4 - 1 = 3$

3 is not equal to 0.

So, 2/ root 3 is not a zero of polynomial 3x²-1.

Answer 2

Step-by-step explanation:

ANSWER:-

p(x) = 3x²-1 is the polynomial

Given zeroes

\frac{ - 1}{ \sqrt{3} }3−1

and

\frac{2}{ \sqrt{3} }32

Simply placing the values in place of x,

If it be comes equal to zero, then it will he known as zeroes of polynomial.

3 {( \frac{ -1 }{ \sqrt{3} } )}^{2} - 13(3−1)2−1

3 \times \frac{1}{ 3} - 13×31−1

1 - 1 = 01−1=0

So , -1/ root 3 is a zero of polynomial.

Placing second one now,

3 {({ \frac{2}{ \sqrt{3}}})}^{2} - 13(32)2−1

3 \times \frac{4}{3} - 13×34−1

4 - 1 = 34−1=3

3 is not equal to 0.

So, 2/ root 3 is not a zero of polynomial 3x²-1.

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