Question

HI FRENDZ
DIS IS A QUE OF CLASS X
QUADRATIC EQUATION
CAN U PLS THEN ME FRM WHICH REFERENCE BOOK DIS QUESTION HAD BEEN TAKEN?​

Answer 1

Given:

1) kt²+2t+3k=0....... (Quadratic Equation)

2) Sum of the Zeroes=Product of the zeroes

To Find:

Value of k= ?

Solution:

kt²+2t+3k=0................ (Given)

Comparing the above equation with

ax²+bx+c=0...... (General form of quadratic eq.)

So, a= k, b= 2 and c=3k

Therefore,

Sum of the roots= -b/a= -2/k

Product of the roots= c/a= 3k/k=3/1

As per the given,

Sum of the zeroes/roots=Product of zeroes

→ -2/k= 3

→ -2=3×k

→ -2=3k

→ k= -2/3

So the value of k is -2/3

Please Write your second question clearly then I can able to solve it.

Answer 2

Answer:

Sum of the roots = product of roots

-2/k=3

K=-2/3