Question

hi friend ,
ABCD is a parallelogram in which angle < DAB =70° and < CBD =55°Find <CDB and <ADB​

Answer 1

Step-by-step explanation:

angle DCB will be 110° as sum of opp. angles in a parallelogram is 180°.now applying ASP in ∆BDC

110°+55°+x=180°

x=15°.

therefore angle CBD= 15°

ANGLE ADB =55° ALTERNATE INTERIOR ANGLE.

Answer 2

$\huge \: \green{ \boxed{ \pink{ \purple{ \mathfrak{\bigstar{answer ♡}}}}}}$

$\huge{ \green{ \ddot{ \smile}}}$

_______________________

sum of opposite angles of parallelogram=180.

by angle sum property:-

110+55+CBD=180

CBD=180-165

CBD=15

SO,

ANGLE ADB=55

BY ALTERNATE INTERIOR ANGLE

____________________

hops this may help you

$\huge{ \purple{ \ddot{ \smile}}}$

$\huge \blue{ \mathfrak{thanks♡</p><p>}}$

$<marquee direction="down"> hops this may help you</p><p>mark my answer as brainliest ❣️<marquee/>$

$<marquee direction="down">(◠‿・)—☆ <marquee/>$