Question

hi friend please give answer rapidly

question number (v)

Answer 1

hey mate! here's your answer!
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${x}^{ - \frac{7}{2} } \times 2{x}^{ - \frac{1}{2} }$

when base are same , exonents add,

$= > 2{x}^{ \frac{ - 7}{2} + ( \frac{ - 1}{2}) }$

$= > 2 {x}^{ \frac{ - 7 - 1}{2} }$

$= > 2 {x}^{ \frac{ - 8}{2} }$

here, -8 can be divided by 2 , so answer will be -4 after division,

$= > 2 {x}^{ - 4}$

since, exponent is negative, so it will divide,

$= > \frac{2}{ {x}^{4} }$

hope you understood!

Answer 2

Solution:

${x}^{ \frac{ - 7}{2} } \times 2 {x}^{ \frac{ - 1}{2} } \\ = {x}^{ \frac{ - 7}{2} } \times \frac{2}{ {x}^{ \frac{1}{2} } } \\ = 2 \times {x}^{ \frac{ - 7}{2} - \frac{1}{2} } \\ = 2 {x}^{ \frac{ - 8}{2} } \\ = 2 {x}^{ - 4}$
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Amrit⭐