Question

hi friends
a answer only 7th question.​

Answer 1

$\green{\bold{\underline{\underline{Solution:}}}}$

Let the consecutive multiplies of 8 be 8x, 8(x+1), 8(x+2)

• A.T.O

$\red{\tt{8x + 8(x+1) + 8(x+2)}}$

Taking 8 as a common Factor

$\pink{\tt{8(x + x+1 + x+2) = 8×111}}$

$\orange{\tt{3x+3 = 111}}$

$\purple{\tt{3x = 111-3}}$

$\blue{\tt{3x = 108}}$

$\large{\red{\tt{x=\frac{108}{3}}}}$

$\boxed{\green{\tt{x = 36}}}$

Multiplies are :

$\boxed{\pink{\tt{8x = 8×36 =288}}}$

$\boxed{\pink{\tt{8x+1 = 8×36+1 = 296}}}$

$\boxed{\pink{\tt{8x+2=8×36+2 = 304}}}$