hi friends can anyone help me
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The area will increase by 56.25%
alishabbeer:
explainn
Let the old side of the square be 'a'.
Let the new side be 'a1′.
After increasing the side of square by 25%,
a1 = a + a×25/100
a1 = a(1+1/4)
=> a1 = (5/4)×a
Old Area of the square = a^2
New Area = a1^2 = ((5/4)×a)^2
= (25/16)a^2
Increase in area = New area - Old area
Increase in area = 25/16×a^2 - a^2 = ((25/16) - 1)a^2 = (9/16)a^2
Percentage increase in area =(9/16)×100 = 56.25%
Let the new side be 'a1′.
After increasing the side of square by 25%,
a1 = a + a×25/100
a1 = a(1+1/4)
=> a1 = (5/4)×a
Old Area of the square = a^2
New Area = a1^2 = ((5/4)×a)^2
= (25/16)a^2
Increase in area = New area - Old area
Increase in area = 25/16×a^2 - a^2 = ((25/16) - 1)a^2 = (9/16)a^2
Percentage increase in area =(9/16)×100 = 56.25%
Answered by
1
let side of square be=a
if it is increased by 25 percent, side will become a/4 (25a/100).
area=(a/4)^2=a^2/16.
but area should be a^2
so area will be 16 times less than original area
if it is increased by 25 percent, side will become a/4 (25a/100).
area=(a/4)^2=a^2/16.
but area should be a^2
so area will be 16 times less than original area
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