Question

hi friends

don't spam

equation of pair of angular bisectors of pair of lines xy+x+y+1=0 is​

Answer 1

Answer

Given the equation is=>

xy +x +y +1 =0

=>x(y+1) +1(y+1)=0

=>(x+1) (y+1)=0

Hence lines are x =-1 and y =-1.

Plz refer to the attachment for the continued answer.

Answer 2

Answer:

x²-y²-2x+2y=0

Step-by-step explanation:

xy+x+y+1

x(y+1)+1(y+1)

(x+1) (y+1)=0

(x+y) (x-y)

x²-y²=0

x=X+h, y=Y+k

x=x-1,y=y-1

(x-1)²-(y-1)²=0

x²+1-2x-(y²+1-2y)=0

x²-y²-2x+2y=0