Question

Hi friends.....
...find dy/dx ​

Answer 1

1/x^(-7/2)=x^(7/2)

$y=x^(^7^/^2^) +8x^1^/^2 +6^(^-^4^/^3^) +4x^3$

$d(x^n)/dx=n*x^(^n^-^1^)$

dy/dx=$7/2*x^(^3^/^2^) +8*1/2*x^(^-^1^/^2^) + 0 + 4/3*x^2$

$dy/dx=7x^(^3^/^2^)/2+4x^(^-^1^/^2^)+4x^2/3$

Hope his helps

Answer 2

Explanation:

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