Question

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The roots of the equation
$\sf\:a(b-c) x^{2} + b(c-a)x + c(a-b) = 0$ are ,

Answer 1

hey mate,

your answer is in the attachment...

Answer 2

_________Heyy Buddy ❤_________

_______Here's your Answer _________

$\sqrt{2} {x}^{2} - 3x + \sqrt{2} = 0 \\ \\ here \: a = \sqrt{2} \: \: \: b = - 3 \: \: and \: c = \sqrt{2.} \\ \\ = > x = \frac{ - b + \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ = > x = \frac{3 + \sqrt{9 - 4 \times 2} }{2 \sqrt{2} } \\ \\ = > x = \frac{3 + \sqrt{1} }{2 \sqrt{2} } \\ \\ = > x = \frac{3 + 1}{2 \sqrt{2} } \\ \\ = > x = \frac{4}{2 \sqrt{2} } \\ \\ = > x = \frac{2}{ \sqrt{2} } \\ \\ = > x = \frac{2}{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ \\ = > x = \frac{2 \sqrt{2} }{2} \\ \\ = > x = \sqrt{2}$

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