Question

hi friends good morning. pls answer this question .​

Answer 1

Answer:

As both of their vertical components of initial velocity equal zero, they are equally fast vertically.

They will reach the ground at the same time. The motion in the 2 perpendicular axis is independent.

Both will reach the ground at time

t=√(2h/g)

h is the height above ground of both balls.

However, as one is horizontally projected, it should be horizontally faster than the other one.

Answer 2

Answer:

Explanation:

For ball A:

Initial velocity=0 m/s

So it accelerates downwards with “g”

Let it cover a height =H in time t

H=0+1/2 gt2

T=√(2H/g)

For second B:

Initial velocity=0 m/s

So it accelerates downwards with “g”

Let it cover a height =H in time t

H=0+1/2 gt2

T1=√(2H/g)