Question

HI FRIENDS!!☺

Hameed has built a cubical water tank with lid for his house,with each outer edge 1.5 m long .He get the outer surface of the tank excluding the base with a square tiles of the side 25 cm. find how much he would spend for the tiles if the cost of the tiles is 360 per dozen

Answer 1

Area of 1 face = 1.5×1.5 = 2.25 = 22500cm

area of 5 faces = 5×22500 = 112500cm

area of 1 tile = 25×25 = 625

So no of tiles = 112500/625 = 180

12 tiles cost 360
180 tiles cost = 360/12 × 180 = 30×180 = 5400

Answer 2

Answer:

Cost of 180 tiles is ₹ 5400

Step-by-step explanation:

Edge of cubical tank = 1.5 m = 150 cm

Surface area of tank = 5 × 150 × 150 cm²

(Since five outer faces of the tank are there)

Area of each tile = side × side

• 25 × 25 cm²

Number of tiles required = $\frac{surface\;area\;of\;tank}{area\;of\;each\;tile}$

• $\frac{5*150*150}{25*25}$

• $180$

Cost of 1 dozen tiles, (12 tiles) = ₹ 360

Cost of 1 tile = $\frac{360}{12}$

• ₹ 30

Cost of 180 tiles = 180 × ₹ 30

• ₹ 5400