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IN triangle APB and CQD
<ABP = <CDQ ( ALTERNATE)
AB = CD ( OPP.sides are equal in parallelogram)
<APB = <CQD = 90
HENCE APB is similar to CQD
As they are similar
SO AP= CQ
<ABP = <CDQ ( ALTERNATE)
AB = CD ( OPP.sides are equal in parallelogram)
<APB = <CQD = 90
HENCE APB is similar to CQD
As they are similar
SO AP= CQ
Answered by
1
hope this will help you!!
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