Question

hi friends help me class 7th maths
Q.no 5

Answer 1

In ∆ AQB AND ∆ APC
AP =AQ (GIVEN)
AB =AC ( GIVEN)
anglePAC = angleBAQ ( both include angle A )
∆ AQB congruent ∆APC (SAS)
BQ =CP (CPCT)

Answer 2

Hey mate, here's your answer -

In ∆ ABQ & ∆ ACP, we have

AB = AC. (GIVEN)

AQ = AP. (GIVEN)

angle A = angle A (COMMON)

therefore, ∆ ABQ is congruent to ∆ACP.

So, BQ = CP. (CPCT).

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