Question

Hi friends....
Please answer me this question....

Answer 1

hi mate

here is your answer

now in trianglepmr,

pr2=pm2+mr2

pr=root over6*6+8*8

 =  root ovr100

  =10

here pr=10

now in trianglr pqr,

qr2=pq2+pr2

26*26=pq2+10*10

pq2=676-100

pq=root ovr576=24

now area of pqr=1/2824810=120cm2

hope this may help youn please mark me as brainliest