Question

— HI FRIENDS — Please find the Zeros of quadratic equations 1/3 , - 2. Best answer will be markde as brainliest ☺

Answer 1

Hey there !

Given that,
Zeroes of quadratic polynomial ( If it's quadratic equation, We won't be calling zeroes) are 1/3 , -2 .

We know that,
Quadratic polynomial with zeroes α , β is
k [ x² - ( α + β ) x + αβ ]

So now,
α = 1/3 , β = -2 .

The required quadratic polynomial
= k [ x² - ( 1/3 - 2 ) x + (1/3)(-2) ]
= k [ x² - ( -5/3 )x - 2/3 ]
= k [ x² + 5/3 x- 2/3 ]

Taking k = 3 .

= 3 ( x² + 5/3x-2/3)
= 3x² + 5x - 2

(Or)

Sum of zeroes = 1/3 - 2 = -5/3

Product zeroes = 1/3 ( -2) = -2/3 .

Required polynomial = k[ x² - (Sum of zeroes) * x + (Product of zeroes) ]

= k [ x² - ( -5/3)x - 2/3 ]

Taking k = 3, will give x² +5x-2 .

Hope helped! ^^