Question

hi friends please solve each and every question and please do not give irrelevant answers or else it would be reported for sure .... please answer fast .....this is for class 10 ......

Answer 1

Answer:

Q 5] ∅ =45    {sin45 = 1/$\sqrt{2}$ and cos 45 = 1/$\sqrt{2}$}

Q6] sinA =1/2 when A=30° hence cotA = cot30 =$\sqrt{3}$/1

Q7] if cos(α+β) = 0 then α+β = 90 ---eq1 (∵cos(90) = 0)

         sin A = cos 90-A hence

         sin (α-β) = cos (90-(α-β))

                       = cos (α+β-α+β)                  [ -×- = +][from eq 1]

                       = cos (2β)

Q8] sorry for this

Step-by-step explanation:

Answer 2

1. Sin theta = cos theta

We can't simply write it as 45 degrees because we need to prove it.

sin theta/ cos theta = 1

sin theta/cos theta = tantheta

tantheta is 1 when theta is 45 degree

Hence theta = 45 degrees

2. sin A = 1/2

cosA = √3/2 (use Pythogorean theorem)

cot A = √3

3. cos(alpha + beta) = 0

We know, cos 900 = 0 therefore (alpha + beta) = 900 i.e. alpha = (900 - beta)

Substituting value of alpha in sin(alpha - beta) we get

sin(900 -beta -beta)

sin(900 - 2beta)

cos2beta because sin(900 - theta) = cos theta

thus, ur answer is cos2beta

4. tantheta + cot theta = 5

hence,

tan theta square + cot theta square = ?

(tan theta + cot theta ) square = tan theta square + cot theta square + 2tan theta cot theta

= 25 = tan theta square + cot theta square + 2 (because tan theta * cot theta = 1)

hence

tan theta square + cot theta square = 23

Hope this helps

I was just tryin to be helpful.

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