Physics, asked by kopl97, 1 year ago

hi friends please solve the 13 the question

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Answered by AJAYMAHICH
2
Initial velocity (u) = 49 m/s    Final velocity (v) = 0 m/s

Gravity in toward down = + 9.8 m/s2  Gravity in toward up = - 9.8 m/s2

(i) We know, V2 - u2 = 2gs

              or,  (o)2- (49)2 = 2 X 9.8 X S

              or,  s = - (49)2/ 2 X 9.8 = 122.5 m

Maximum height = 122.5 m

(ii) We know, v = u + gt

              or   0 = 49 +(- 9.8) X t

              or   9.8 X t =  49

              or, t = 49/ 9.8 = 5 s

If, time for upward direction = time for downward direction

Then, total time taken by a ball to return back = 5 + 5 = 10 s

Answered by rajk123654987
1

Hey there !

( i ) Initial Velocity = 49 m/s

Final Velocity = 0 m/s

Acceleration = - 9.8 m/s ( -g )

Formula = s = ut + at² / 2 => Formula 1

But we dont know time. So time can be calculated by using the formula,

v = u + at

=> 0 = 49 - 9.8 t

=> 9.8 t = 49

=> t = 49 / 9.8 = 5 seconds

So substituting all the values in Formula 1 we get,

s = 49 ( 5 ) - 9.8 * 5² / 2

=> s = 245 - 9.8 * 25 / 2

=> s = 245 - 245 / 2

=> s = 245 - 122.5

=> s = 122.5 m

Hence the ball would travel 122.5 m

( ii ) While going it takes 5 seconds and while coming it again takes 5 seconds. Hence Total time taken is 10 seconds.

Hope my answer helped !

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