Math, asked by realsujaykumar, 1 year ago

Hi friends please solve this puzzle ...

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Answers

Answered by TheLifeRacer
0
Hey !!!

Nice question .

if we counting the alphabets in increasing order then ,

i is at the place of 9th no.
F is at the place of 5th no.

so, I+ F= 14 ------1)

Now , in 2nd term .

We want to find alphabates of which is replaced ,

? , E , C

so, we can find the place of alphabets in increasing order

so, E alphabates is at the place of 5th no.
C is at the place of 3 no.

? + E + C = ? + 5 + 3 = ? + 8 ---------2)

Now in last term is

E and G

so, E is at the place 5th no . of an alphabates in increasing order

and G is at the place of 7th no .

so , sum of

E + G= 5 + 7 = 12

now in there are three condition we see
1st condition. I + C = 14
2nd condition , ? + E + C =? +8
3rd condition , E+ G = 12

now , if we look at the top to the bottom then you can get the serious in decreasing order with difference of 1 . like that 14 , 13 , 12 then this series will be completed .

then, let's think .. which alphabates can fullfil their requirements.

so, ? + E + C = 8 +? = 13

8 + ? = 13

? = 5

at the 5th position which alphabates comes up that is E so the answer is E

[E ]which fullfill the condition in decreasing with 1 difference in each term .

E E C Answer

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Hope it helps you !!!

@Rajukumar111

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Answered by vanshika7187
0

The answer is E

hope it helps you

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