Question

hi friends ♥ ♥
pls help me with this question ​

Answer 1

When three coins are tossed simultaneously, the total possible outcomes are {(H,H,H) , (H,H,T) , (H,T,H) , (H,T,T), (T,H,H), (T,H,T), (T,T,H), (T,T,T)}.

The total no. of outcomes = 8.

therefore p( getting atleast one head)= 7/8

By the way nice handwriting