Hi Friends,
Prove that ∆ ABC is isosceles if median AD is perpendicular to BC.
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Class - 9th
Chapter - Triangle
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Solution :-
Given :- A ∆ABC , in which median AD is ⊥to BC.
To prove :- ∆ABC is Isosceles.
Proof :- In ∆ ABD and ∆ ACD ,
We have ,
⇒BD = DC(Given)
⇒∠ ADB = ∠ADC ( Each = 90°)
⇒AD = AD ( Common side)
⇒∆ ABD ≌ ∆ ACD ( By SAS )
⇒AB = AC ( ∵ C.P.C.T )
∴ ∆ ABC is an isosceles triangles. Proved.
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