Question

Hi Friends,

The diameter of a garden roller is 1.4 m and its 2 m long. How much area will it cover in 5 revolution ?

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Class - 9th
Chapter - Surface area & Volume

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Answer 1

Answer:

radius= 0.7

area=2*22/7*0.7*2

=8.8m2

area covered in 5 revolution =5*8.8

44.0m2

Step-by-step explanation:

hope it helps you

Answer 2

ᴀɴsᴡᴇʀ:

• Area levelled of a garden in 5 revolutions is 44m^2

Step-by-step explanation:

$\bold{Radius \: of \: a \: garden \: roller(r) = \frac{1.4}{2} = 0.7 m }$

$\bold{length \: of \: the \: garden \: roller (h) = 2 m}$

$\bold{∴ Curved \: surface \: area \: of \: garden \: roller = 2πrh }$

$\bold{So,}$

= 2 × 22/7 × 0.7 × 2

$\bold{the \: area \: levelled \: of \: a \: garden \:roller \: in \: one \:revolution \: is \: 8.8 m^{2} }$

$\bold{Now, }$

$\bold{area \: levelled \: of \: a \: garden \: in \: 5 \: revolutions = 8.8 \: \times 5 \: = 44 \: m^{2}  }$