Question

hi friends





the length of a rectangular park exceeds its breadth by 17 meters.if the perimeter of the park is 178 meters.find the dimensions of the park?

​

Answer 1

let the breadth be x

therefore length of the rectangular park will be x+17

given

2(x+x+17)=178

2(2x+17)=178

2x+17=89

2x=72

x=36

the length =53

Answer 2

GIVEN:

• The length of a rectangular park exceeds its breadth by 17 meters
• The perimeter of the park is 178 meters

TO FIND:

• What is the length and breadth of the rectangular park ?

SOLUTION:

Let the length of the park be 'L' m and breadth of the park be 'B' m

➝ The length of a rectangular park exceeds its breadth by 17 meters

According to question:-

$\bf{ L = B + 17....1)}$

We know that the formula for finding the perimeter of rectangular park is:-

$\bf{ Perimeter = 2(Length + Breadth)}$

On putting the values in the formula we get

$\rm{\mapsto 178 = 2(B + 17 + B)}$

$\rm{\mapsto 178 = 2(2B + 17 )}$

$\rm{\mapsto \cancel\dfrac{178}{2} = 2B+ 17}$

$\rm{\mapsto 89 = 2B + 17}$

$\rm{\mapsto 89-17 = 2B}$

$\rm{\mapsto 72 = 2B }$

$\rm{\mapsto B = \cancel\dfrac{72}{2}}$

$\bf{\mapsto B = 36\: m}$

❝ The Breadth of the park is 36 m ❞

Put the value of B in equation 1)

$\rm{\mapsto L = 36 + 17}$

$\bf{\mapsto L = 53 \: m}$

❝ The Length of the park is 53 m ❞

_____________________