Question

hi

from the following figure prove that: AB>CD
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Answer 1

Answer:

abc=70 & acd=40

IAM sure it will be helpful

bcz were reading this chapter now adays

Answer 2

Solution

$\:\: \underline{\underline{\bf{\large\mathfrak\red{~~Solution~~}}}}$

from the ∆ABC....we get...

AB=AC(as this is an isosceles triangle)

now ..ang(A)=ang(ACB)=70°

so ..ang(ACD)=180°-70°=110°

now ..

ang(ADC)=40°

ang (ACD)=110°

therefore...ang(CAD)=180°(110°+40°)=30°

CD is the opposite side of ang(CAD)

and ..AC is the opposite side of ang(ADC)

now ..we know that the opposite side of a larger angle is large compare to to the other..

so..

=>ang(CAD)>ang(ADC)

=>AC>CD

=>AB>CD. [as ..AC=AB]. (proved)

$:\: \underline{\underline{\bf{\large\mathfrak{~hope ~this ~help~you~~}}}}$