Hi good morning friends solve questions no.17 & 18
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Hey here is your answer
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17.
In triangle BDE
/B + /D + /E = 180°
80° + 70° + /E = 180°
/E = 180° - 150°
/E = 30°
18.
In concyclic trapezium ABCD
/A = /D
then,
/A = /D = 100°
/D = 100°
___________________________
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@ajaman. .............
_____________________
17.
In triangle BDE
/B + /D + /E = 180°
80° + 70° + /E = 180°
/E = 180° - 150°
/E = 30°
18.
In concyclic trapezium ABCD
/A = /D
then,
/A = /D = 100°
/D = 100°
___________________________
Hope it may helpful to you
plzzz mark me as brainlist
@ajaman. .............
Sajiyakhan786:
wrong answer
Answered by
1
HEY DEAR....
HERE'S YOUR ANSWER⬇
QUESTION NO. 17 :-
We know that :
# FDB is a triangle.
# Sum of angles of a triangle = 180°.
So,
# Ang.F+Ang.B+Ang.D=180°.
# 70°+80°+Ang.D=180°.
Therefore :
# Ang.D=180°-150°.
# Ang.D=30°.
So,
The right answer is (a).
QUESTION NO. 18 :-
We know that
# Ang.A+Ang.D=180°.
We also know that,
# Ang.A=100°.
So,
# Ang.D=180°-100°.
# Ang.D=80°.
Therefore,
The right answer is (a).
Any doubts, please ask me in the comments.
I HOPE YOU FIND IT HELPFUL.
@ LB :)
HERE'S YOUR ANSWER⬇
QUESTION NO. 17 :-
We know that :
# FDB is a triangle.
# Sum of angles of a triangle = 180°.
So,
# Ang.F+Ang.B+Ang.D=180°.
# 70°+80°+Ang.D=180°.
Therefore :
# Ang.D=180°-150°.
# Ang.D=30°.
So,
The right answer is (a).
QUESTION NO. 18 :-
We know that
# Ang.A+Ang.D=180°.
We also know that,
# Ang.A=100°.
So,
# Ang.D=180°-100°.
# Ang.D=80°.
Therefore,
The right answer is (a).
Any doubts, please ask me in the comments.
I HOPE YOU FIND IT HELPFUL.
@ LB :)
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