hi guys can u please tell a3+b3=------------
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Answered by
1
a³+b³ = (a+b) (a²-ab+b²)
Hope it helps u...!!!
✴️Do mark as brainliest if helps✴️
Hope it helps u...!!!
✴️Do mark as brainliest if helps✴️
Answered by
2
bolaa dear....here is your answer.....✨✨✨✨
Let us derive it by using identity (a−b)3(a−b)3
(a−b)3=a3−3a2b+3ab2−b3(a−b)3=a3−3a2b+3ab2−b3
(a−b)3=a3−3ab(a−b)−b3(a−b)3=a3−3ab(a−b)−b3
(a−b)3+3ab(a−b)=a3−b3(a−b)3+3ab(a−b)=a3−b3
(a−b)[(a−b)2+3ab]=a3−b3(a−b)[(a−b)2+3ab]=a3−b3
(a−b)[a2−2ab+b2+3ab]=a3−b3(a−b)[a2−2ab+b2+3ab]=a3−b3
(a−b)[a2+ab+b2]=a3−b3(a−b)[a2+ab+b2]=a3−b3
Hope it helps.......❤️❤️❤️❤️
Let us derive it by using identity (a−b)3(a−b)3
(a−b)3=a3−3a2b+3ab2−b3(a−b)3=a3−3a2b+3ab2−b3
(a−b)3=a3−3ab(a−b)−b3(a−b)3=a3−3ab(a−b)−b3
(a−b)3+3ab(a−b)=a3−b3(a−b)3+3ab(a−b)=a3−b3
(a−b)[(a−b)2+3ab]=a3−b3(a−b)[(a−b)2+3ab]=a3−b3
(a−b)[a2−2ab+b2+3ab]=a3−b3(a−b)[a2−2ab+b2+3ab]=a3−b3
(a−b)[a2+ab+b2]=a3−b3(a−b)[a2+ab+b2]=a3−b3
Hope it helps.......❤️❤️❤️❤️
Anonymous:
thank u dear frend
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