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Cos A = Cos 3A / (2 Cos 2A - 1)
Cos 15° = Cos 45° / (2 Cos 30° - 1)
Cos 15° = (1/√2) / ( 2*√3/2 - 1)
Cos 15° =( 1/√2 ) / ( √3 - 1 )
Cos 15° = (√3 - 1 ) / 2
Cos 15° = Cos 45° / (2 Cos 30° - 1)
Cos 15° = (1/√2) / ( 2*√3/2 - 1)
Cos 15° =( 1/√2 ) / ( √3 - 1 )
Cos 15° = (√3 - 1 ) / 2
siddhartharao77:
A small correction. it should be root 3 + 1 in the finsl step!
*final
no you calculate wrong sir...
hmm your answer answer was correct
but i calculate to according this question
Thats answer remains same for any question!
ohh.m sorry
i think i read something wrong
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The answer is explained in the attachment.
Hope it helps!
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