Hi guys could u plz help me with this question......
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Heya...
Here's your answer.........
Given zeroes are α =1, β =-3
i) sum of zeroes = α+β = 1-3 = -2 ----(1)
ii) product of the zeroes = αβ =1(-3) = -3 ----(2)
Required quadratic polynomial = x² - (α+β)x+αβ
= x² -(-2)x +(-3)
=x²+2x-3
compare this with ax²+bx+c
a= 1, b= 2 , c= -3
sum of the zeroes = -b/a = - 2/1 = -2 [ this is equal to (1)]
product of the zeroes = c/a = -3/1 = -3 [this is equal to (2)]
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✨✨✨✨BY BeWaFa ✨✨✨
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Thanks...!!!
XD
Sorry baby 'wink'
chrislin:
thank you so so muchhhh
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