Question

Hi guys

determine the AP whose third term is 5 and seventh term is 9

Answer 1

Answer:

3 , 4 , 5 , 6......

Step-by-step explanation:

Third term of an AP = 5

a+2d = 5

a = 5-2d.....(1)

Again,

Seventh term of an AP = 9

a+6d = 9.......(2)

Putting the value of A in equation (2)

a+6d = 9

5-2d +6d = 9

4d = 9-5

4d = 4

D = 4/4

d = 1.

Putting the value of D In equation (1)

a = 5-2d

a = 5-2 × 1 = 5-2 = 3

Therefore,

First term of an AP = 3

Second term = a+d = 3+1 = 4

Third term = a+2d = 3 +2 × 1 = 3+2 = 5

Four term = a+3d = 3 + 3 × 1 = 3+3 = 6

AP = a , a+d , a+2d , a+3d.....

=> 3 , 4 , 5 , 6......

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