HI GUYS
GOOD AFTERNOON
SOLVE THIS QUESTION
PLEASE........Xd
Answers
Let us draw a rough sketch of the required quadrilateral and write down the dimensions. Clearly, the two easily constructible triangles are LIT and LIF.
Steps of construction:
1. Draw LI = 4 cm
2. With L as centre and radius 2.5 cm, draw an arc.
3. With I as centre and radius 4 cm draw another arc to cut the previous arc at T.
4. Join TL and TL
5. With L as centre and radius 4.5 cm, draw an arc.
6. With I as centre and radius 3 cm, draw another arc to cut the previously drawn arc at F.
7. Join FI, FL and TF.
Then, LIFT is the required quadrilateral.
(ii) Steps of construction:
1. Draw OL = 7.5 cm.
2. With L as centre and radius equal to 5 cm cut an arc.
3. With O as centre and radius equal to 10 cm, cut another arc on the arc drawn in step-2 at point D.
4. With L as centre and radius equal to 6 cm, cut another arc.
5. With D as centre and radius equal to 6 cm cut on arc drawn in step-4 at point G.
6. Join LD, LG, OG, OD and DG.
Hence GOLD is the required quadrilateral.
<Judge it yourself...>
Step-by-step explanation:
We can define quadrilaterals as polygons that have four sides.
1. Construct quadrilaterals when four sides and one diagonal is given.
Construct a quadrilateral PQRS where PQ = 4 cm, Oq = 6 cm, RS = 5 cm, PS = 5.5 cm and PR= 7 cm
Quadrilaterals
Draw Δ PQR using SSS construction condition.
With P as the centre, draw an arc of radius 5.5 cm.
With R as the centre, draw an arc of radius 5 cm.
S is the point of intersection of the two arcs. Also, mark S and complete PQRS.
PQRS is the required quadrilateral.
2. Construct quadrilaterals when four sides and one diagonal is given.
Construct a quadrilateral ABCD where BC = 4.5 cm, AD = 5.5 cm, CD = 5cm and the diagonal AC = 5.5 cm, diagonal BD = 7 cm
Quadrilaterals
Draw ΔACD using SSS construction condition
Taking D as the centre, draw an arc of radius 7 cm.
Now let C be the centre, draw an arc of radius 4.5 cm
Since B lies on both the arcs, B is the point intersection of the two arcs.
Mark B and complete ABCD.
ABCD is the required quadrilateral.
hope it's helpful for you...
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