Math, asked by Anonymous, 10 months ago

HI GUYS

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SOLVE THIS QUESTION
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Answers

Answered by MrEccentric
3

Let us draw a rough sketch of the required quadrilateral and write down the dimensions. Clearly, the two easily constructible triangles are LIT and LIF.

Steps of construction:

1. Draw LI = 4 cm

2. With L as centre and radius 2.5 cm, draw an arc.

3. With I as centre and radius 4 cm draw another arc to cut the previous arc at T.

4. Join TL and TL

5. With L as centre and radius 4.5 cm, draw an arc.

6. With I as centre and radius 3 cm, draw another arc to cut the previously drawn arc at F.

7. Join FI, FL and TF.

Then, LIFT is the required quadrilateral.

(ii) Steps of construction:

1. Draw OL = 7.5 cm.

2. With L as centre and radius equal to 5 cm cut an arc.

3. With O as centre and radius equal to 10 cm, cut another arc on the arc drawn in step-2 at point D.

4. With L as centre and radius equal to 6 cm, cut another arc.

5. With D as centre and radius equal to 6 cm cut on arc drawn in step-4 at point G.

6. Join LD, LG, OG, OD and DG.

Hence GOLD is the required quadrilateral.

<Judge it yourself...>

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Answered by hardikrakholiya21
2

Step-by-step explanation:

We can define quadrilaterals as polygons that have four sides.

1. Construct quadrilaterals when four sides and one diagonal is given.

Construct a quadrilateral PQRS where PQ = 4 cm, Oq = 6 cm, RS = 5 cm, PS = 5.5 cm and PR= 7 cm

Quadrilaterals

Draw Δ PQR using SSS construction condition.

With P as the centre, draw an arc of radius 5.5 cm.

With R as the centre, draw an arc of radius 5 cm.

S is the point of intersection of the two arcs. Also, mark S and complete PQRS.

PQRS is the required quadrilateral.

2. Construct quadrilaterals when four sides and one diagonal is given.

Construct a quadrilateral ABCD where BC = 4.5 cm, AD = 5.5 cm, CD = 5cm and the diagonal AC = 5.5 cm, diagonal BD = 7 cm

Quadrilaterals

Draw ΔACD using SSS construction condition

Taking D as the centre, draw an arc of radius 7 cm.

Now let C be the centre, draw an arc of radius 4.5 cm

Since B lies on both the arcs, B is the point intersection of the two arcs.

Mark B and complete ABCD.

ABCD is the required quadrilateral.

hope it's helpful for you...

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